Import Question JSON

Current Question (ID: 21266)

Question:

$\text{The correct match among the following is:}$ $1.\ \text{Hexane-2-one and Hexane-3-one} \quad \text{Position isomers.}$ $2.\ \text{Pentane-3-one and Pentane-2-one} \quad \text{Functional isomers.}$ $3.\ \text{2-Pentene and 1-Pentene} \quad \text{Metamers.}$ $4.\ \text{Pentanoic acid and Hexanoic acid} \quad \text{Functional isomers.}$

Options:

1. $\text{Hexane-2-one and Hexane-3-one: Position isomers.}$
2. $\text{Pentane-3-one and Pentane-2-one: Functional isomers.}$
3. $\text{2-Pentene and 1-Pentene: Metamers.}$
4. $\text{Pentanoic acid and Hexanoic acid: Functional isomers.}$

Solution:

$\text{Hint: Hexane-2-one and Hexane-3-one are position isomers.}$ $\text{Explanation:}$ $(i)\ \text{Positional isomers are constitutional isomers with the same carbon skeleton and will have the same functional group.}$ $\text{They differ from each other in the position of the functional groups on the carbon chain and the phenomenon is known as positional isomerism.}$ $\text{Hexane-2-one and Hexane-3-one are position isomers.}$ $(ii)\ \text{Functional isomers are structural isomers with the same molecular formula (that is, the same number of atoms of the same elements) but distinct atom connections, resulting in dissimilar groupings.}$ $\text{Pentane-3-one and Pentane-2-one are not functional isomers. These are positional isomers.}$ $(iii)\ \text{Metamers are the isomers having the same molecular formula but different alkyl groups on two sides of functional groups.}$ $\text{So, the option 1 is the correct match.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}