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Current Question (ID: 21272)

Question:
$\text{Which of the following is/are used as adsorbent in adsorption chromatography?}$
Options:
  • 1. $\text{Silica gel}$
  • 2. $\text{Alumina}$
  • 3. $\text{Benzene}$
  • 4. $\text{Both (1) and (2)}$
Solution:
$\text{Adsorption Chromatography involves the analytical separation of a chemical mixture based on the interaction of the adsorbate with the adsorbent.}$ $\text{The mixture of gas or liquid gets separated when it passes over the adsorbent bed that adsorbs different compounds at different rates.}$ $\text{For adsorption chromatography, the adsorbent is used as the stationary phase.}$ $\text{The solute binds to the adsorbent via van der Waal forces and steric interactions.}$ $\text{Since the adsorption sites are typically only on the outer surface of the stationary phase, fairly small particles are used as the stationary phase.}$ $\text{Some commonly used adsorbents are Silica gel H, silica gel G, silica gel N, silica gel S, hydrated gel silica, cellulose microcrystalline, alumina, modified silica gel, etc.}$ $\text{Hence, option 4 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}