Import Question JSON

Current Question (ID: 21273)

Question:

$\text{The basic strength of the following anions, ordered from most to least, is:}$ $\text{OH}^-, \text{HCOO}^-, \text{CH}_3\text{COO}^-, \overline{\text{OR}}$ $(I) \quad (II) \quad (III) \quad (IV)$

Options:

1. $II > III > I > IV$
2. $IV > I > III > II$
3. $III > IV > I > II$
4. $I > IV > II > III$

Solution:

$\text{Hint: Basic strength} \propto \frac{1}{\text{Strength of conjugate acid}}$ $\text{The stronger an acid, the weaker its conjugate base; conversely, the stronger a base, the weaker its conjugate acid.}$ $\text{For the given anions, the strength of conjugate acid is as follows:}$ $\text{HCOOH} > \text{CH}_3\text{COOH} > \text{H}_2\text{O} > \text{ROH}$ $\text{Formic acid is more acidic than acetic acid because the methyl group in acetic acid shows +I effect and decreases the acidity of the compound.}$ $\text{Similarly, alcohol is less acidic than water due to the presence of an electron-donating group (alkyl group) which destabilizes the alkoxide ion.}$ $\text{Thus, the basic strength: } \overline{\text{RO}} > \text{OH}^- > \text{CH}_3\text{COO}^- > \text{HCOO}^-$ $\text{Thus, option 2 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}