Import Question JSON

Current Question (ID: 21275)

Question:

$\text{What is the correct order of acidic strength for the following acids?}$ $\text{HCOOH, CH}_3\text{COOH, CH}_3\text{CH}_2\text{COOH,}$ $\text{CH}_3\text{CH}_2\text{CH}_2\text{COOH}$

Options:

1. $\text{HCOOH} < \text{CH}_3\text{COOH} < \text{CH}_3\text{CH}_2\text{COOH} < \text{CH}_3\text{CH}_2\text{CH}_2\text{COOH}$
2. $\text{HCOOH} > \text{CH}_3\text{CH}_2\text{CH}_2\text{COOH} > \text{CH}_3\text{COOH} > \text{CH}_3\text{CH}_2\text{COOH}$
3. $\text{HCOOH} > \text{CH}_3\text{COOH} > \text{CH}_3\text{CH}_2\text{COOH} > \text{CH}_3\text{CH}_2\text{CH}_2\text{COOH}$
4. $\text{CH}_3\text{COOH} > \text{HCOOH} > \text{CH}_3\text{CH}_2\text{COOH} > \text{CH}_3\text{CH}_2\text{CH}_2\text{COOH}$

Solution:

$\text{Hint: See the +I effect on Acidic strength.}$ $\text{Explanation:}$ $\text{The acidic strength of carboxylic acids decreases as the +I effect of}$ $\text{the alkyl group attached to the carboxylic group increases. The +I}$ $\text{effect of electron-releasing alkyl groups increases the negative}$ $\text{charge of the carboxylate ion, making it unstable. This makes it}$ $\text{harder to lose a proton.}$ $\text{In contrast, an electron-withdrawing (-I) effect increases the acidic}$ $\text{strength of a carboxylic acid. A negative charge on the -COO- group is}$ $\text{stabilized by an electron-withdrawing group.}$ $\text{Therefore, the correct order of acidic strength of the given acids is:}$ $\text{HCOOH > CH}_3\text{COOH > CH}_3\text{CH}_2\text{COOH >}$ $\text{CH}_3\text{CH}_2\text{CH}_2\text{COOH}$ $\text{Hence, option 3 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}