Import Question JSON

Current Question (ID: 21278)

Question:

$\text{Arrange the following in increasing order of their stability:}$ $\begin{array}{ll} \text{a.} & \overset{\oplus}{\text{CH}_2} \text{--- CH = C --- H} \\ \text{b.} & \text{CH}_2 = \text{CH} \overset{\oplus}{\overset{\text{O}}{\underset{\ominus}{\text{C}}}} \text{--- H} \\ \text{c.} & \text{CH}_2 = \text{CH} \overset{\ominus}{\overset{\text{O}}{\underset{\oplus}{\text{C}}}} \text{--- H} \\ \text{d.} & \overset{\ominus}{\text{CH}_2} \text{--- CH = C --- H} \overset{\oplus}{\text{O}} \end{array}$

Options:

1. $(a) < (b) < (c) < (d)$
2. $(a) < (d) < (c) < (b)$
3. $(a) < (c) < (d) < (b)$
4. $(d) < (c) < (a) < (b)$

Solution:

$\text{The stability of the given ionic species will be decided by the fact that}$ $\text{the positive charge on the more electronegative element will be less}$ $\text{stable and as the distance between opposite charges increases,}$ $\text{stability decreases.}$ $\text{Among the given compounds, (a) and (b) are more stable than (c)}$ $\text{and (d) because the negative charge is on the more electronegative}$ $\text{oxygen element and the positive charge is on the carbon atom.}$ $\text{(b) is more stable than (a) because of less distance between}$ $\text{opposite charges. Similarly, (c) is more stable than (d) because of}$ $\text{less distance in between the positive and negative charges.}$ $\text{Therefore, the correct stability order is: (d) < (c) < (a) < (b)}$ $\text{Hence, option 4 is the correct choice.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}