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Current Question (ID: 21289)

Question:

$\text{Identify the number of compounds, among the following, that have the same degree of unsaturation:}$ $\text{(A) } \text{CH}_3 - \text{CH} = \text{CH} - \text{C} \equiv \text{N}$ $\text{(B) } \text{CH}_3 - \text{N} = \text{CH} - \text{C} \equiv \text{CH}$ $\text{(C) } \text{CH} \equiv \text{C} - \text{NH} - \text{CH} = \text{CH}_2$ $\text{(D) } \text{CH}_2 = \text{CH} - \text{CH}_2 - \text{C} \equiv \text{N}$

Options:

1. $2$
2. $3$
3. $0$
4. $4$

Solution:

$\text{Degree of unsaturation} = \text{Number of } \pi \text{ bonds} + \text{Number of rings}$ $\text{CH}_3\text{CH} = \text{CH} - \text{C} \equiv \text{N} = 2 + 1 = 3$ $\text{CH}_3 - \text{N} = \text{CH} - \text{C} \equiv \text{CH} = 2 + 1 = 3$ $\text{CH} \equiv \text{C} - \text{NH} - \text{CH} = \text{CH}_2 = 2 + 1 = 3$ $\text{CH}_2 = \text{CH} - \text{CH}_2 - \text{C} \equiv \text{N} = 2 + 1 = 3$ $\text{All the compounds have 3 as degree of unsaturation}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}