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Current Question (ID: 21302)

Question:
$\text{The major product [R] in the following sequence of reactions is:}$ $\text{HC} \equiv \text{CH} \xrightarrow{(i) \text{LiNH}_2/\text{ether}} \xrightarrow{(ii) \text{H}_3\text{C} \text{CHBr} \text{(CH}_3\text{)}_2\text{CH}} \xrightarrow{(i) \text{HgSO}_4/\text{H}_2\text{SO}_4} \xrightarrow{(ii) \text{NaBH}_4} \xrightarrow{\text{Conc. } \text{H}_2\text{SO}_4, \Delta} \text{[R]}$
Options:
  • 1. $\text{H}_2\text{C} = \text{CH}_2 - \text{CH}_3 \text{CH(CH}_3\text{)}_2$
  • 2. $\text{H}_3\text{C} - \text{C} \equiv \text{CH} - \text{CH}_3 \text{CH}_2\text{CH}$
  • 3. $\text{H}_3\text{C} - \text{C} \equiv \text{C(CH}_3\text{)}_2 \text{CH}_3\text{CCH}_2$
  • 4. $\text{(CH}_3\text{)}_2\text{CH} - \text{C} \equiv \text{CH}_2$
Solution:
$\text{Hint: Alkyne reacts with HgSO}_4 / \text{H}_2\text{SO}_4 \text{ and ketone is obtained as a product.}$ $\text{In the first reaction, acid-base reaction take place followed by substitution reaction.}$ $\text{The second reaction is an example of electrophilic addition reaction.}$ $\text{In the second reaction, ketone is obtained as a product.}$ $\text{The ketone reacts with NaBH}_4 \text{ and convert into an alcohol.}$ $\text{Hence, Q is an alcohol.}$ $\text{In the last reaction, dehydration reaction take place and an alcohol is converted into an alkene.}$ $\text{The reactions are as follows:}$ $\text{HC} \equiv \text{CH} \xrightarrow{(i) \text{LiNH}_2/\text{ether}} \xrightarrow{(ii) \text{Br}} \text{CH}_3\text{CH} = \text{CCH} \xrightarrow{(i) \text{HgSO}_4/\text{H}_2\text{SO}_4} \xrightarrow{(ii) \text{NaBH}_4} \text{OH} \xrightarrow{\text{H}^+/\Delta} \text{CH}_3\text{CH}_2\text{CH}_3 \text{CH}_3\text{CCH}_3 \text{(major)}$

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{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}