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Current Question (ID: 21315)

Question:

$\text{Which of the following compounds is non-aromatic?}$

Options:

1. $\text{Compound with S}$
2. $\text{Biphenyl}$
3. $\text{Cyclopentadienyl anion}$
4. $\text{Cyclopenta-2,3-diene}$

Solution:

$\text{Hint: Aromatic compound is planar and follows Huckel's rule.}$ $\text{When deciding if a compound is aromatic, go through the following checklist. If the compound does not meet all the following criteria, it is likely not aromatic.}$ $1. \text{The molecule is cyclic (a ring of atoms).}$ $2. \text{The molecule is planar (all atoms in the molecule lie in the same plane).}$ $3. \text{The molecule is fully conjugated (p orbitals at every atom in the ring).}$ $4. \text{The molecule has } (4n + 2)\pi \text{ electrons (n= 0 or any positive integer).}$ $\text{The compound that is not aromatic is as follows:}$ $\text{The cyclopenta-2,3-diene is non-aromatic compound because the ring contains } sp^3 \text{ carbon atom. In aromatic system, all ring carbon must be } sp^2 \text{ hybridised.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}