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Current Question (ID: 21321)

Question:

$\text{Identify the intermediate [A] in the following reaction:}$ $\left( \text{C}_6\text{H}_5\text{COO} \right)_2 \xrightarrow{\Delta} \text{A} \rightarrow 2\cdot\text{C}_6\text{H}_5 + 2\text{CO}_2$

Options:

1. $\text{C}_6\text{H}_5 - \overset{\cdot}{\text{C}} = \overset{\cdot}{\text{O}}$
2. $\text{C}_6\text{H}_5 - \overset{\cdot}{\text{C}} = \overset{\cdot}{\text{O}}$
3. $\text{C}_6\text{H}_5 - \overset{\cdot}{\text{C}} = \overset{\cdot}{\text{O}}$
4. $\text{C}_6\text{H}_5 - \overset{\cdot}{\text{C}} = \text{O}$

Solution:

$\text{The intermediate [A] in the above reaction is}$ $\text{C}_6\text{H}_5 - \overset{\cdot}{\text{C}} = \overset{\cdot}{\text{O}}$ $\text{Benzoate radical is formed as intermediate.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}