Import Question JSON

Current Question (ID: 21334)

Question:

$\text{The product formed in the reaction given below is:}$ $\text{(Image of reaction with } \text{HBr and heat)}$

Options:

1. $\text{(Image of option 1)}$
2. $\text{(Image of option 2)}$
3. $\text{(Image of option 3)}$
4. $\text{(Image of option 4)}$

Solution:

$\text{Hint: Ring expansion and methyl shift take place in the mechanism.}$ $\text{Explanation: In the first step when given alkene reacts with HBr then tertiary carbocation is formed.}$ $\text{In the next step, ring expansion takes place, the four-membered ring is converted into a five-membered ring.}$ $\text{The five-membered ring is more stable than a four-membered ring.}$ $\text{In the next step, methyl shift takes place and secondary carbocation is converted into a tertiary carbocation.}$ $\text{In the last step, tertiary carbocation reacts with Br}^- \text{ and alkyl bromide is formed as a product.}$ $\text{The mechanism of the reaction is as follows:}$ $\text{(Image of reaction mechanism)}$ $\text{Thus, option 4 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}