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Current Question (ID: 21335)

Question:
$\text{Consider the following reactions:}$ $\text{2-Methylpropene} \xrightarrow{\text{Cold alkaline } \text{KMnO}_4} \text{P}$ $\text{2-Methylpropene} \xrightarrow{\text{Hot } \text{KMnO}_4} \text{Q}$ $\text{The products P and Q, respectively, are:}$
Options:
  • 1. $\begin{array}{c} \text{OH} \\ | \\ \text{CH}_2 \end{array} \text{C} \begin{array}{c} \text{OH} \\ | \\ \text{CH} \\ | \\ \text{CH}_3 \end{array} \text{CH}_3 \text{ and } \begin{array}{c} \text{OH} \\ | \\ \text{CH}_3 \end{array} \text{CH} \begin{array}{c} \text{OH} \\ | \\ \text{CH}_3 \end{array}$
  • 2. $\begin{array}{c} \text{OH} \\ | \\ \text{CH}_2 \end{array} \text{C} \begin{array}{c} \text{OH} \\ | \\ \text{CH} \\ | \\ \text{CH}_3 \end{array} \text{CH}_3 \text{ and } \begin{array}{c} \text{O} \\ || \\ \text{C} \\ | \\ \text{CH}_3 \end{array} \text{CH}_3$
  • 3. $\begin{array}{c} \text{O} \\ || \\ \text{CH}_3 \end{array} \text{C} \begin{array}{c} \text{O} \\ || \\ \text{C} \\ | \\ \text{CH}_3 \end{array} \text{CH}_3 \text{ and } \text{HCOOH}$
  • 4. $\text{HCOOH and } \begin{array}{c} \text{OH} \\ | \\ \text{CH}_3 \end{array} \text{CH} \begin{array}{c} \text{OH} \\ | \\ \text{CH}_3 \end{array}$
Solution:
$\text{Hint: Hot } \text{KMnO}_4 \text{ is a stronger oxidising agent than cold alkaline } \text{KMnO}_4$ $\text{Explanation:}$ $\text{Alkenes, on reaction with a cold aqueous alkaline solution of potassium permanganate, are oxidised to vicinal dihydroxy compounds called glycols.}$ $\text{When 2-methylpropene is oxidized with hot, concentrated acidic potassium permanganate solution, it produces acetone, carbon dioxide, and water.}$ $\text{The given reaction proceeds as follows:}$ $\text{2-Methylpropene} \xrightarrow{\text{Cold alkaline } \text{KMnO}_4} \begin{array}{c} \text{OH} \\ | \\ \text{CH}_2 \end{array} \text{C} \begin{array}{c} \text{OH} \\ | \\ \text{CH} \\ | \\ \text{CH}_3 \end{array} \text{CH}_3$ $\text{2-Methylpropene} \xrightarrow{\text{Hot } \text{KMnO}_4} \begin{array}{c} \text{O} \\ || \\ \text{C} \\ | \\ \text{CH}_3 \end{array} \text{CH}_3 + \text{CO}_2$ $\text{So, option 2 is the correct choice.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}