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Current Question (ID: 21340)

Question:
$\text{Consider the following sequence of reactions and identify the unknown reagents (A) and (B) respectively.}$ $\text{CH}_3 - \text{CH}_2 - \text{CH}_2 - \text{Br} \xrightarrow{(A)} \text{P} \xrightarrow{(B)} \text{CH}_3 - \text{CHBr} - \text{CH}_3 \text{ (Major)}$
Options:
  • 1. $(A) : \text{Dil. aq NaOH at } 20^\circ\text{C} \quad (B) : \text{HBr, CH}_3\text{COOH}$
  • 2. $(A) : \text{Dil. aq NaOH at } 20^\circ\text{C} \quad (B) : \text{Br}_2, \text{CHCl}_3$
  • 3. $(A) : \text{Alc. NaOH at } 80^\circ\text{C} \quad (B) : \text{HBr, CH}_3\text{COOH}$
  • 4. $(A) : \text{Alc. NaOH at } 80^\circ\text{C} \quad (B) : \text{Br}_2, \text{CHCl}_3$
Solution:
$\text{Hint: Elimination reaction then addition reactions of HBr.}$ $\text{When 1-bromopropane reacts in the presence of alcoholic NaOH, then it undergoes dehydrohalogenation to form 1-propene as a product. It is an elimination reaction.}$ $\text{When propene reacts with hydrogen bromide (HBr), the reaction is an example of an electrophilic addition reaction which produces 2-bromopropane as the final product. The reaction follows Markovnikov's rule, which states that the negative part of the adding molecule attaches to the carbon atom with the fewest hydrogen atoms.}$ $\text{Thus, option 3 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}