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Current Question (ID: 21344)

Question:
$\text{Which of the following molecules is aromatic?}$
Options:
  • 1. $\text{Option 1}$
  • 2. $\text{Option 2}$
  • 3. $\text{Option 3}$
  • 4. $\text{Option 4}$
Solution:
$\text{Hint: Use Huckel's Rule of aromaticity.}$ $\text{Step 1: There are four criteria for aromaticity as follows:}$ $\text{(a) The molecule is cyclic (a ring of atoms)}$ $\text{(b) The molecule is planar (all atoms in the molecule lie in the same plane)}$ $\text{(c) The molecule is fully conjugated (p orbitals at every atom in the ring)}$ $\text{(d) The molecule has } (4n + 2) \pi \text{ electrons (n=0 or any positive integer)}$ $\text{Step 2:}$ $\text{Among the given compounds, only phenanthrene is an aromatic compound. Other compounds have } sp^3 \text{ hybridized carbon atoms which makes them non-aromatic.}$ $\text{Phenanthrene is another polycyclic aromatic hydrocarbon but unlike anthracene, its three benzene rings are fused in an angular arrangement.}$ $\text{Although phenanthrene's structure is slightly non-planar due to steric interactions between hydrogen atoms at the fusion points of the rings, it is still sufficiently planar for the } \pi \text{-electrons to be delocalized across the molecule.}$ $\text{Although phenanthrene is slightly less stable than benzene due to the strain introduced by the angular fusion of the rings. The slight non-planarity of phenanthrene does not completely disrupt the conjugation of } \pi \text{-electrons. The delocalization of } \pi \text{-electrons still occurs, making the molecule aromatic.}$ $\text{Phenanthrene is more stable than anthracene due to the larger stability of the } \pi \text{-system of the former, which is more aromatic.}$ $\text{Hence, option 2 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}