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Current Question (ID: 21346)

Question:

$\text{In the given reaction, identify compounds } A \text{ and } B:$ $\text{CH}_3\text{C}_6\text{H}_5 \xrightarrow{\text{Cl}_2 (2 \text{ eq}), \text{hv}} A \xrightarrow{(i) \text{NaOH} \\ (ii) \text{dil. HCl}} B$

Options:

1. $(A) \ \text{CH}_2\text{Cl} \ \text{(B)} \ \text{COOH}$
2. $(A) \ \text{CHCl}_2 \ \text{(B)} \ \text{COOH}$
3. $(A) \ \text{CHCl}_2 \ \text{(B)} \ \text{CHO}$
4. $(A) \ \text{CH}_2\text{Cl} \ \text{(B)} \ \text{CHO}$

Solution:

$\text{Hint: Free radical halogenation reaction at the benzylic position for product } (A).$ $\text{Explanation:}$ $\text{Tolune reacts with chlorine in the presence of light to give (dichloromethyl)benzene.}$ $\text{The reaction substitutes two hydrogen atoms on the methyl group with chlorine atoms.}$ $\text{(Dichloromethyl)benzene reacts with NaOH, followed by dilution with HCl, to yield benzaldehyde.}$ $\text{The base-catalyzed hydrolysis of the alkyl dihalide forms a geminal diol, which is unstable and loses water to form an aldehyde, i.e., benzaldehyde.}$ $\text{Hence, option 3 is the correct answer.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}