Import Question JSON

Current Question (ID: 21366)

Question:

$\text{The decreasing order of electrical conductivity of the following aqueous solutions is:}$ $0.1 \text{ M Formic acid (A),}$ $0.1 \text{ M Acetic acid (B),}$ $0.1 \text{ M Benzoic acid (C)}$

Options:

1. $\text{A > B > C}$
2. $\text{A > C > B}$
3. $\text{C > B > A}$
4. $\text{C > A > B}$

Solution:

$\text{Hint: Electrical conductivity depends on the number of ions}$ $\text{The electrical conductivity depends on the number of ions. As the number of ions increases electrical conductivity also increases.}$ $\text{More acid will generate more number of ions and show more electrical conductivity.}$ $\text{Benzoic acid itself is a somewhat stronger acid than acetic acid. The carboxyl group of benzoic acid is attached to an sp}^2\text{-hybridized carbon which is more electronegative and electron-withdrawing than the sp}^3\text{-hybridized carbon attached to acetic acid.}$ $\text{The acidic order of given acid is as follows:}$ $\text{Formic acid > benzoic acid > acetic acid}$ $\text{The } pK_a \text{ value of given acids are as follows:}$ $\text{Formic acid = 3.75}$ $\text{Acetic acid = 4.75}$ $\text{Benzoic acid = 4.20}$ $\text{Hence, decreasing order of electrical conductivity is A > C > B}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}