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Current Question (ID: 21384)

Question:

$\text{The EMF of a cell is given as 0.83 V. The cell can be represented as:}$ $\text{Ti|Ti}^{+}(0.001\text{M})||\text{Cu}^{2+}(0.01\text{M})|\text{Cu}}$ $\text{The EMF of this cell could be increased by:}$

Options:

1. $\text{increasing conc. of } \text{Cu}^{2+}, \text{ keeping conc. of } \text{Ti}^{+} \text{ constant.}$
2. $\text{increasing conc. of } \text{Ti}^{+}, \text{ keeping conc. of } \text{Cu}^{2+} \text{ constant.}$
3. $\text{increasing conc. of both } \text{Ti}^{+} \text{ and } \text{Cu}^{2+}. $
4. $\text{decreasing conc. of both } \text{Cu}^{2+} \text{ and } \text{Ti}^{+}. $

Solution:

$\text{Hint: Use the Nernst equation and analyze the cell reactions.}$ $\left( \text{TI} \rightarrow \text{TI}^{+} + e^{-} \right) \times 2$ $\frac{\text{Cu}^{2+} + 2e^{-} \rightarrow \text{Cu}}{2\text{TI} + \text{Cu}^{2+} \rightarrow 2\text{TI}^{+} + \text{Cu}}$ $E_{\text{cell}} = E^{\circ}_{\text{cell}} - \frac{0.0591}{2} \log \frac{[\text{TI}^{+}]^2}{[\text{Cu}^{2+}]}$ $E_{\text{cell}} \text{ will increase if we}$ $\text{(i) Decrease } \text{TI}^{+}$ $\text{(ii) Increase } \text{Cu}^{2+}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}