Import Question JSON

Current Question (ID: 21400)

Question:

$4.5 \text{ g of compound A (MW = 90) was used to make 250 mL of its aqueous solution.}$ $\text{The molarity of the solution in M is } x \times 10^{-1}. \text{ The value of } x \text{ is } \underline{\phantom{x}}. \text{ (Rounded off to the nearest integer)}$

Options:

1. $5$
2. $4$
3. $2$
4. $1$

Solution:

$\text{Hint: Molarity} = \frac{\text{Number of mole of A}}{\text{volume of solution}}$ $\text{Step 1:}$ $\text{Given values are as follows:}$ $\text{Amount of substance} = 4.5 \text{ g}$ $\text{The molar mass of substance} = 90$ $\text{Volume of solution} = 250 \text{ mL}$ $\text{Step 2:}$ $\text{Calculate the value of molarity as follows:}$ $M = \frac{4.5}{90} \times \frac{1}{250 \times \frac{1}{1000} \text{ L}}$ $M = 0.2 \text{ or } 2 \times 10^{-1}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}