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Current Question (ID: 21414)

Question:
$\text{The degree of dissociation (}\alpha\text{) of a weak electrolyte, } \text{A}_x\text{B}_y \text{ is related to van't Hoff factor (}i\text{) by the expression:}$
Options:
  • 1. $\alpha = \frac{i-1}{(x+y-1)}$
  • 2. $\alpha = \frac{i-1}{x+y+1}$
  • 3. $\alpha = \frac{x+y-1}{i-1}$
  • 4. $\alpha = \frac{x+y+1}{i-1}$
Solution:
$\text{Hint: Use the formula, that is, } \alpha = \frac{i-1}{n-1}$ $\text{The reaction is as follows:}$ $\text{A}_x\text{B}_y \rightarrow x\text{A}^{+y} + y\text{B}^{-x}$ $\text{It is a dissociation reaction. The relation between } i \text{ and } \alpha \text{ is as follows:}$ $\alpha = \frac{i-1}{n-1}$ $\text{n is the total number of particles, A}^{+y} \text{ generates } x \text{ particles, and B}^{-x} \text{ generates } y \text{ particles.}$ $\text{Total particles (n) = } x + y$ $\text{The value of } \alpha \text{ is as follows:}$ $\alpha = \frac{i-1}{x+y-1}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}