Import Question JSON

Current Question (ID: 21417)

Question:
$\text{A binary liquid solution is prepared by mixing n-heptane and ethanol.}$ $\text{Which one of the following statements is correct regarding the}$ $\text{behavior of the solution?}$
Options:
  • 1. $\text{The solution formed is an ideal solution}$
  • 2. $\text{The solution is non-ideal, showing +ve deviation from Raoult's Law}$
  • 3. $\text{The solution is non-ideal, showing -ve deviation from Raoult's Law}$
  • 4. $\text{n-heptane shows +ve deviation while ethanol shows -ve deviation}$ $\text{from Raoult's Law.}$
Solution:
$\text{Hint: interaction between n-hexane and n-hexane molecules and}$ $\text{ethanol and ethanol molecules is more than the interaction between}$ $\text{hexane and ethanol molecule.}$ $\text{When a solution does not obey Raoult's law over the entire range of}$ $\text{concentration, then it is called a non-ideal solution. The cause for}$ $\text{these deviations lies in the nature of interactions at the molecular}$ $\text{level.}$ $\text{In the case of positive deviation from Raoult's law, A-B interactions}$ $\text{are weaker than those between A-A or B-B, i.e., in this case, the}$ $\text{intermolecular attractive forces between the solute-solvent}$ $\text{molecules are weaker than those between the solute-solute and}$ $\text{solvent-solvent molecules.}$ $\text{The n-hexane and ethanol form a non-ideal solution. The n-hexane is}$ $\text{a nonpolar compound and ethanol is a polar compound. The}$ $\text{interaction between n-hexane and n-hexane molecules and ethanol}$ $\text{and ethanol molecules is more than the interaction between hexane,}$ $\text{and ethanol molecule.}$ $\text{Thus, option second is correct.}$

Import JSON File

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}