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Current Question (ID: 21430)

Question:
$\text{Which of the following has more relative lowering in vapour pressure}$ $\text{at the same temperature}$ $1.\ 0.1\ \text{M urea}$ $2.\ 0.1\ \text{M NaCl}$ $3.\ 0.1\ \text{M sucrose}$ $4.\ 0.1\ \text{M CaCl}_2$
Options:
  • 1. $0.1\ \text{M urea}$
  • 2. $0.1\ \text{M NaCl}$
  • 3. $0.1\ \text{M sucrose}$
  • 4. $0.1\ \text{M CaCl}_2$
Solution:
$\text{Relative lowering of vapor pressure is a colligative property and}$ $\text{colligative property depends only on the amount of solute.}$ $\frac{\Delta P}{P^o_{\text{solvent}}} = i X_{\text{solute}}$ $\Delta P = \text{Lowering of vapor pressure}$ $P^o_{\text{solvent}} = \text{Pure state pressure of solvent}$ $X_{\text{solute}} = \text{Mole fraction of solute}$ $i = \text{Van't hoff factor}$ $\text{From above we can say that}$ $\frac{\Delta P}{P^o_{\text{solvent}}} = \alpha i$ $\text{A. Urea} \rightarrow \text{non electrolyte, therefore, } i = 1$ $\text{B. NaCl} \rightarrow \text{electrolyte, therefore, } i = 2$ $\text{C. Sucrose} \rightarrow \text{non electrolyte, therefore, } i = 1$ $\text{D. CaCl}_2 \rightarrow \text{electrolyte, therefore, } i = 3$ $\text{Hence the CaCl}_2 \text{ solution will show maximum relative lowering in}$ $\text{vapor pressure.}$

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{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}