Import Question JSON

Current Question (ID: 21437)

Question:

$\text{For the compound } \text{MX}_2, \text{ the observed mass is } 65.6, \text{ while the normal mass is } 164. \text{ The percentage degree of ionization of } \text{MX}_2 \text{ (rounded to the nearest integer) is:}$ $1. \ 75$ $2. \ 60$ $3. \ 50$ $4. \ 85$

Options:

1. $75$
2. $60$
3. $50$
4. $85$

Solution:

$\text{Hint: } i = \frac{\text{Normal molar mass}}{\text{Observed molar mass}}$ $\text{MX}_2 \rightarrow \text{M}^{+2} + 2\text{X}^{-}$ $i = \frac{\text{normal molar mass}}{\text{observed molar mass}}$ $i = \frac{164}{65.6}$ $1 + (3 - 1)\alpha = \frac{164}{65.6}$ $2\alpha = \frac{98.4}{65.6}$ $\alpha = 0.75$ $\text{percent dissociation } = 75\%$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}