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Current Question (ID: 21510)

Question:

$\text{The differential rate law for the following reaction expressed as:}$ $\text{H}_2 + \text{I}_2 \rightarrow 2\text{HI}$

Options:

1. $-\frac{d[\text{H}_2]}{dt} = -\frac{d[\text{I}_2]}{dt} = 2\frac{d[\text{HI}]}{dt}$
2. $-2\frac{d[\text{H}_2]}{dt} = -2\frac{d[\text{I}_2]}{dt} = \frac{d[\text{HI}]}{dt}$
3. $\frac{d[\text{H}_2]}{dt} = \frac{d[\text{I}_2]}{dt} = \frac{d[\text{HI}]}{dt}$
4. $-\frac{d[\text{H}_2]}{2dt} = -\frac{d[\text{I}_2]}{2dt} = \frac{d[\text{HI}]}{dt}$

Solution:

$\text{Hint: Rate of reaction} = \frac{1}{\text{stoichiometric coefficient}} \left(\frac{\text{change in concentration}}{\text{change in time}}\right)$ $\text{Calculate the rate of the reaction as follows:}$ $\text{H}_2 + \text{I}_2 \rightarrow 2\text{HI}$ $\text{Rate of reaction} = -\frac{d[\text{H}_2]}{dt} = -\frac{d[\text{I}_2]}{dt} = \frac{1}{2}\frac{d[\text{HI}]}{dt}$ $-2\frac{d[\text{H}_2]}{dt} = -2\frac{d[\text{I}_2]}{dt} = \frac{d[\text{HI}]}{dt}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}