Import Question JSON

Current Question (ID: 21514)

Question:

$\text{For a first-order reaction, a half-life } (t_{1/2}) \text{ is 50 min. The time } t_{3/4} \text{ (in minutes) of the reaction is:}$ $1.\ 75$ $2.\ 100$ $3.\ 125$ $4.\ 50$

Options:

1. $75$
2. $100$
3. $125$
4. $50$

Solution:

$\text{Answer (100)}$ $t_{3/4} \text{ is the time taken for consumption of } \frac{3}{4} \text{ of the reactant and it is equal to 2 times the } t_{1/2}.$ $1 \xrightarrow{t_{1/2}} \frac{1}{2} \xrightarrow{t_{1/2}} \frac{1}{4}$ $\text{Therefore, } t_{3/4} \text{ will be 100 minutes.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}