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Current Question (ID: 21523)

Question:
$\text{Given below are two statements:}$ $\text{Statement I: CeO}_2 \text{ can be used for the oxidation of aldehydes and ketones.}$ $\text{Statement II: Aqueous solution of EuSO}_4 \text{ is a strong reducing agent.}$ $\text{In the light of the above statements, choose the correct answer from the options given below:}$
Options:
  • 1. $\text{Statement I is false but statement II is true}$
  • 2. $\text{Statement I is true but statement II is false}$
  • 3. $\text{Both statement I and statement II are true}$
  • 4. $\text{Both statement I and statement II are false}$
Solution:
$\text{The +3 oxidation state of lanthanide is most stable and therefore lanthanide in +4 oxidation state has strong tendency to gain e}^- \text{ and converted into +3 and therefore act as strong oxidizing agent.}$ $\text{eg Ce}^{4+} \text{ And therefore CeO}_2 \text{ is used to oxidized alcohol aldehyde and ketones.}$ $\text{Lanthanide in +2 oxidation state has strong tendency to loss e}^- \text{ and converted into +3 oxidation state therefore act as strong reducing agent.}$ $\therefore \text{EuSO}_4 \text{ act as strong reducing agent.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}