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Current Question (ID: 21531)

Question:
$\text{The electrode potential of } \text{M}^{2+} / \text{M} \text{ of 3d-series elements shows positive value of:}$ $1. \text{ Zn}$ $2. \text{ Fe}$ $3. \text{ Co}$ $4. \text{ Cu}$
Options:
  • 1. $\text{Zn}$
  • 2. $\text{Fe}$
  • 3. $\text{Co}$
  • 4. $\text{Cu}$
Solution:
$\text{Hint: Copper show a positive electrode potential value of } \text{M}^{2+}/\text{M}$ $\text{because the sum of enthalpies of sublimation and ionization is not balanced by hydration enthalpy}$ $\text{Only copper shows a positive value for electrode potential of } \text{M}^{2+}/\text{M} \text{ of 3d-series elements.}$ $\text{E}^{\Theta} (\text{Cu}^{2+}/\text{Cu}) = +0.34$ $\text{E}^{\Theta} (\text{Zn}^{2+}/\text{Zn}) = -0.76$ $\text{E}^{\Theta} (\text{Fe}^{2+}/\text{Fe}) = -0.44$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}