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Current Question (ID: 21532)

Question:

$\text{The incorrect statement is:}$

Options:

1. $\text{Manganate and permanganate ions are paramagnetic.}$
2. $\text{Manganate ion is green in color and permanganate ion is purple in color.}$
3. $\text{In manganate and permanganate ions, the } \pi\text{-bonding, takes place by overlap of p-orbitals of oxygen and d-orbitals of manganese.}$
4. $\text{Manganate and permanganate ions are tetrahedral.}$

Solution:

$\text{Option 1) Manganate } = \text{MnO}_4^{2-}$ $\text{Permanganate } \Rightarrow \text{MnO}_4^{-}$ $\text{hybridisation of Mn } \Rightarrow d^3s$ $\text{Mn } \Rightarrow \begin{array}{cccc} \uparrow & \uparrow & \uparrow & \uparrow \end{array} \ 3d^5 \ 4s^2$ $\text{After excitation}$ $\text{Mn } \Rightarrow \begin{array}{cccc} \uparrow & \uparrow & \uparrow & \uparrow & \uparrow \end{array} \ 3d^5 \ 4p$ $\text{MnO}_4^{2-}$ $2 \times 2P_\pi - 3d_\pi$ $1 \times 2P_\pi - 4d_\pi$ $(2) \ \text{MnO}_4^{2-} = \text{Green}$ $\text{MnO}_4^{-} = \text{purple/violet}$ $(3) \ \text{Manganate contains 1 unpaired electron hence it is paramagnetic.}$ $\text{whereas permanganate contains no unpaired electrons hence it is diamagnetic.}$ $(4) \ \text{Both have } d^3s \text{ hybridisation hence both have tetrahedral geometry}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}