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Current Question (ID: 21554)

Question:
$\text{An element from the d-block of the } 4^{\text{th}} \text{ period has a spin-only magnetic moment of } 3.9 \text{ BM in its } \text{Z}^{3+} \text{ ionic form. What is the minimum atomic number } (\text{Z}) \text{ of this element?}$
Options:
  • 1. $29$
  • 2. $23$
  • 3. $24$
  • 4. $25$
Solution:
$\mu = 3.9 \text{BM}$ $\text{It means there must be } 3 \text{ unpaired electrons in } \text{Z}^{3+} \text{ ion}$ $\text{Cr}^{+3} \Rightarrow [\text{Ar}]3d^3 4s^0$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}