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Current Question (ID: 21566)

Question:
$\text{Which of the following oxidation reactions are carried out by both } \text{K}_2\text{Cr}_2\text{O}_7 \text{ and } \text{KMnO}_4 \text{ in acidic medium?}$ $\text{A. } \text{I}^- \rightarrow \text{I}_2$ $\text{B. } \text{S}^{2-} \rightarrow \text{S}$ $\text{C. } \text{Fe}^{2+} \rightarrow \text{Fe}^{3+}$ $\text{D. } \text{I}^- \rightarrow \text{IO}_3^-$ $\text{E. } \text{S}_2\text{O}_3^{2-} \rightarrow \text{SO}_4^{2-}$ $\text{Choose the correct answer from the options given below:}$
Options:
  • 1. $\text{B, C and D only}$
  • 2. $\text{A, D and E only}$
  • 3. $\text{A, B and C only}$
  • 4. $\text{C, D and E only}$
Solution:
$\text{Hint: Both } \text{K}_2\text{Cr}_2\text{O}_7 \text{ and } \text{KMnO}_4 \text{ are strong oxidizing agents in an acidic medium.}$ $\text{In an acidic medium, both } \text{K}_2\text{Cr}_2\text{O}_7 \text{ and } \text{KMnO}_4 \text{ act as oxidizing agents, but } \text{KMnO}_4 \text{ is generally a stronger oxidizing agent than } \text{K}_2\text{Cr}_2\text{O}_7. \text{ KMnO}_4 \text{ can oxidize a wider range of substances and is more reactive in acidic conditions.}$ $\text{In an acidic medium, both can convert an anion to a neutral molecule and a cation to the next higher oxidation state.}$ $\text{The given reactions can take place in the following medium:}$ $\text{I}^- \xrightarrow{\text{H}^+} \text{I}_2$ $\text{I}^- \xrightarrow{\text{OH}^-} \text{IO}_3^-$ $\text{S}^{2-} \xrightarrow{\text{H}^+} \text{S}$ $\text{S}_2\text{O}_3^{2-} \xrightarrow{\text{OH}^-} \text{SO}_4^{2-}$ $\text{S}_2\text{O}_3^{2-} \xrightarrow{\text{H}^+} \text{S} \downarrow + \text{SO}_4^{2-}$ $\text{Hence, option 3 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}