Import Question JSON

Current Question (ID: 7331)

Question:

$\text{The correct match is:}$ $\begin{array}{|c|c|c|c|} \hline \text{List I} & & \text{List II} & \\ \hline \text{a.} & \text{Micro} & \text{i.} & 10^{-15} \text{ m} \\ \hline \text{b.} & \text{Mega} & \text{ii.} & 10^{-6} \text{ m} \\ \hline \text{c.} & \text{Giga} & \text{iii.} & 10^{6} \text{ m} \\ \hline \text{d.} & \text{Femto} & \text{iv.} & 10^{9} \text{ m} \\ \hline \end{array}$ $\text{Codes:}$ $\begin{array}{|c|c|c|c|c|} \hline & \text{a} & \text{b} & \text{c} & \text{d} \\ \hline \text{1.} & \text{i} & \text{iv} & \text{iii} & \text{ii} \\ \hline \text{2.} & \text{iii} & \text{iv} & \text{ii} & \text{i} \\ \hline \text{3.} & \text{ii} & \text{iii} & \text{iv} & \text{i} \\ \hline \text{4.} & \text{i} & \text{iii} & \text{iv} & \text{ii} \\ \hline \end{array}$

Options:

1. $\text{a-i, b-iv, c-iii, d-ii}$
2. $\text{a-iii, b-iv, c-ii, d-i}$
3. $\text{a-ii, b-iii, c-iv, d-i}$
4. $\text{a-i, b-iii, c-iv, d-ii}$

Solution:

$\text{Hint: Prefixes used in the SI system}$ $\text{The correct order of prefixes with their multiples are as follows:}$ $\text{Match the following:}$ $\begin{array}{|c|c|} \hline \text{List I} & \text{List II} \\ \hline \text{a. Micro} & \text{i. } 10^{-6} \text{ m} \\ \hline \text{b. Mega} & \text{iii. } 10^{6} \text{ m} \\ \hline \text{c. Giga} & \text{iv. } 10^{9} \text{ m} \\ \hline \text{d. Femto} & \text{v. } 10^{-15} \text{ m} \\ \hline \end{array}$ $\text{Therefore, the correct matching is: a-ii, b-iii, c-iv, d-i}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}