Import Question JSON

Current Question (ID: 7339)

Question:
$\text{If the mass of air at sea level is } 1034 \text{ g cm}^{-2}\text{, pressure in pascal will be:}$
Options:
  • 1. $1.01332 \times 10^5 \text{ Pa}$
  • 2. $1.01332 \times 10^6 \text{ Pa}$
  • 3. $1.01332 \times 10^7 \text{ Pa}$
  • 4. $1.01332 \times 10^8 \text{ Pa}$
Solution:
\text{Hint: Pressure is defined as a force acting per unit area of the surface.} \text{Step 1: Find out pressure} \text{Pressure} = \frac{1034 \text{ g} \times 9.8 \text{ m/s}^2}{1 \text{ cm}^2} = 1034 \times 9.8 \times \frac{10^{-3} \text{ kg}}{10^{-4} \text{ m}^2} = 1034 \times 9.8 \times 10 \text{ kg/m}^2 = 101332 \text{ N/m}^2 \text{Step 2: Write down the pressure in terms of Pascal} \text{We know: } 1 \text{ N} = 1 \text{ kg⋅m/s}^2 \text{Therefore: } 1 \text{ Pa} = 1 \text{ N/m}^2 = 1 \text{ kg⋅m}^{-1}\text{s}^{-2} \text{Pressure} = 1.01332 \times 10^5 \text{ Pa}

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}