Import Question JSON

Current Question (ID: 7344)

Question:

$\text{The incorrect statement among the following is:}$

Options:

1. $\text{A molecule of a compound has atoms of different elements.}$
2. $\text{A compound cannot be separated into its constituent elements by the physical method of separation.}$
3. $\text{A compound retains the physical properties of its constituent elements.}$
4. $\text{The ratio of atoms of different elements in a compound is fixed.}$

Solution:

$\text{Hint: Compound contains two or more than two elements combined together in a fixed proportion by mass.}$ $\text{A compound is a pure substance containing two or more than two elements combined together in a fixed proportion by mass and which can be decomposed into its constituent elements by suitable chemical methods.}$ $\text{Further, the properties of a compound are quite different from the properties of constituent elements.}$ $\text{e.g., water is a compound containing hydrogen and oxygen combined together in a fixed proportion. But the properties of water are completely different from its constituents, hydrogen and oxygen.}$ $\text{Therefore, statement 3 is incorrect - a compound does NOT retain the physical properties of its constituent elements.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}