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$\text{Hint: Apply the law of reciprocal proportions}$\n\n$\text{The definition of the law of reciprocal proportions is: If two different elements combine separately with the same weight as a third element, the ratio of the masses in which they do so is either the same or a simple multiple of the mass ratio in which they combine.}$\n\n$\text{The CS}_2, \text{CO}_2, \text{and SO}_2 \text{follow law of reciprocal proportions.}$\n\n$\text{Let's examine the combining elements and their weights in these compounds:}$\n\n$\text{1. CS}_2\text{: Carbon (C) combines with Sulfur (S)}$\n\n$\text{ • Atomic weight of C = 12}$\n\n$\text{ • Atomic weight of S = 32}$\n\n$\text{ • Combining ratio: 12:64 (1:5.33)}$\n\n$\text{2. CO}_2\text{: Carbon (C) combines with Oxygen (O)}$\n\n$\text{ • Atomic weight of C = 12}$\n\n$\text{ • Atomic weight of O = 16 (32 for O}_2\text{)}$\n\n$\text{ • Combining ratio: 12:32 (1:2.67)}$\n\n$\text{3. SO}_2\text{: Sulfur (S) combines with Oxygen (O)}$\n\n$\text{ • Atomic weight of S = 32}$\n\n$\text{ • Atomic weight of O = 16 (32 for O}_2\text{)}$\n\n$\text{ • Combining ratio: 32:32 (1:1)}$\n\n$\text{Now the weight of S and O is combined in the ratio of 1:1.}$\n\n$\text{We can see that the ratio in which S and O combine together (1:1) is related to the ratios in which they separately combine with C. This illustrates the law of reciprocal proportions.}$\n\n$\text{Therefore, option 3 (CS}_2, \text{CO}_2, \text{SO}_2\text{) is the correct answer.}$