Import Question JSON

Current Question (ID: 7354)

Question:

$\text{The formula of an acid is HXO}_2\text{. The mass of 0.0242 moles of the acid is 1.657 g.}$\n\n$\text{The atomic weight of X is:}$

Options:

1. $35.5$
2. $28.1$
3. $128$
4. $19.0$

Solution:

$\text{Hint: Number of moles} = \frac{\text{amount of HXO}_2}{\text{molar mass of HXO}_2}$\n\n$\text{mass of 0.0242 moles of the acid = 1.657 g}$\n\n$\text{mass of 1 mole of acid = molecular mass of acid = 1.657/0.0242 = 68.47 g}$\n\n$\text{molecular mass of HXO}_2 = 1 + \text{x} + 32 = 68.47$\n\n$\text{x} = 68.47 - 33 = 35.47$\n\n$\text{The atomic mass of x = 35.47 g/mol is chlorine}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}