Import Question JSON

Current Question (ID: 7356)

Question:

$\text{The haemoglobin from the red blood corpuscles contains approximately 0.33\% iron by mass. The molar mass of haemoglobin is 67,200. The number of iron atoms in each molecule of haemoglobin is:}$\n\n$(\text{atomic mass of iron}=56):$

Options:

1. $2$
2. $3$
3. $4$
4. $5$

Solution:

$\text{Hint: 0.33\% of iron by mass means in 100 amu 0.33 amu iron is present.}$\n\n$100 \text{ amu sample} \equiv 0.33 \text{ amu iron}$\n\n$\therefore 67200 \text{ amu} \equiv 221.8 \text{ amu iron}$\n\n$\therefore \text{Number of iron atoms per molecule of haemoglobin} = \frac{221.8}{56} \approx 4.$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}