Import Question JSON

Current Question (ID: 7364)

Question:

$\text{At 100}^{\circ}\text{C and 1 atm, if the density of liquid water is 1.0 g cm}^{-3} \text{ and that of water vapor is 0.0006 g cm}^{-3}\text{, then the volume occupied by water molecules in 1 litre of steam at that temperature will be:}$

Options:

1. $6 \text{ cm}^3$
2. $60 \text{ cm}^3$
3. $0.6 \text{ cm}^3$
4. $0.06 \text{ cm}^3$

Solution:

$\text{Hint: density} = \frac{\text{Mass}}{\text{Volume}}$\n\n$\text{Mass = Volume} \times \text{Density}$\n\n$1000 \times 0.0006$\n\n$= 0.6 \text{ gram}$\n\n$\text{V} = \frac{\text{M}}{\text{d}} = \frac{0.6}{1} = 0.6$\n\n$\text{Volume} = 0.6 \text{ cm}^3$\n\n$\text{Hence, option third is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}