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Current Question (ID: 7365)

Question:

$\text{If N}_A \text{ is Avogadro's number, then the number of valence electrons in 4.2 g of nitride ions (N}^{3-}\text{) will be:}$

Options:

1. $3.2 \text{ N}_A$
2. $1.6 \text{ N}_A$
3. $2.4 \text{ N}_A$
4. $1.2 \text{ N}_A$

Solution:

$\text{Hint: Apply the concept of Avogadro's law}$\n\n$\text{Explanation:}$\n\n$\text{Step 1: Calculate the number of moles of N}^{3-} \text{ as follows:}$\n\n$\text{The given mass of N}^{3-} = 4.2 \text{ g}$\n\n$\text{The molar mass of N}^{3-} = 14 \text{ g mol}^{-1}$\n\n$\text{Hence, the number of moles of N}^{3-} = \frac{4.2 \text{ g}}{14 \text{ g mol}^{-1}} = 0.3 \text{ mol}$\n\n$\text{Step 2: The number of valence electrons in N}^{3-} \text{ is 8}$\n\n$\text{Thus, the number of valence electrons in N}^{3-} = 0.3 \text{ mol} \times \text{N}_A \times 8 = 2.4 \text{ N}_A$\n\n$\text{Option 3 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}