Import Question JSON

Current Question (ID: 7368)

Question:

$\text{An element X has the following isotopic composition,}$\n\n$^{200}\text{X : 90\%, }^{199}\text{X : 8.0\%, }^{202}\text{X : 2.0\%}$\n\n$\text{The weighted average atomic mass of the naturally occurring element X is closest to:}$

Options:

1. $205 \text{ u}$
2. $220 \text{ u}$
3. $196 \text{ u}$
4. $200 \text{ u}$

Solution:

$\text{Hint: Weight of isotopes = natural abundance} \times \text{molar mass}$\n\n$\text{Weight of }^{200}\text{X} = 0.90 \times 200 = 180.00 \text{ u}$\n\n$\text{Weight of }^{199}\text{X} = 0.08 \times 199 = 15.92 \text{ u}$\n\n$\text{Weight of }^{202}\text{X} = 0.02 \times 202 = 4.04 \text{ u}$\n\n$\text{Total weight} = 199.96 = 200 \text{ u}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}