Import Question JSON

Current Question (ID: 7374)

Question:

$\text{Which of the following statements is correct?}$

Options:

1. $\text{1 mole of electrons weights 5.4 mg .}$
2. $\text{1 mole of electrons weights 5.4 kg.}$
3. $\text{1 mole of electrons weights 0.54 mg.}$
4. $\text{1 mole of electrons has } 1.6 \times 10^{-19} \text{ C of charge.}$

Solution:

$\text{Hint: 1 electron weight} = 9.1 \times 10^{-31} \text{ kg}$ $\text{Calculate 1 mole of electrons weighs as follows:}$ $= 9.1 \times 10^{-31} \text{ kg} \times 6.023 \times 10^{23}$ $= 54 \times 10^{-8} \text{ kg}$ $= 54 \times 10^{-8} \times 1000 = 54 \times 10^{-5} \text{ g}$ $= 54 \times 10^{-5} \times 10^3 \text{ mg}$ $= 54 \times 10^{-2} \text{ mg}$ $= 0.54 \text{ mg.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}