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Current Question (ID: 7378)

Question:
$\text{Given below are two statements:}$ $\text{Assertion (A):}$ $\text{One atomic mass unit is defined as one-twelfth of the mass of one carbon-12 atom.}$ $\text{Reason (R):}$ $\text{The carbon-12 isotope is the most abundant isotope of carbon and has been chosen as the standard.}$
Options:
  • 1. $\text{Both (A) and (R) are True and (R) is the correct explanation of (A).}$
  • 2. $\text{Both (A) and (R) are True but (R) is not the correct explanation of (A).}$
  • 3. $\text{(A) is True but (R) is False.}$
  • 4. $\text{(A) is False but (R) is True.}$
Solution:
$\text{Hint: The carbon atom had been used as a reference while assigning atomic mass to the elements of the periodic table.}$ $\text{According to the standard definition of the atomic unit of mass, it is defined as accurately } \frac{1}{12} \text{ of the mass of a carbon-12 atom. It is true Carbon-12 isotope is the most abundant isotope of carbon and has been chosen as the standard. The percentage of C-12 isotope is 98.93\%.}$ $\text{But the correct reason - Carbon-12 is the standard while measuring the atomic masses. Because no other nuclides other than carbon-12 have exactly whole-number masses in this scale.}$ $\text{This is due to two factors:}$ $\text{[1] the different mass of neutrons and protons acting to change the total mass in nuclides with proton/neutron ratios other than the 1:1 ratio of carbon-12; and}$ $\text{[2] an exact whole-number will not be located if there exists a loss/gain of mass to difference in mean binding energy relative to the mean binding energy for carbon-12}$ $\text{Hence, both assertion and reason are true and the reason is not the correct explanation of assertion.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}