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Current Question (ID: 7386)

Question:
$\text{In an iron oxide, the mass percent of iron and oxygen are 69.9 and 30.1, respectively. The empirical formula of the oxide of iron will be:}$
Options:
  • 1. $\text{Fe}_3\text{O}_2$
  • 2. $\text{Fe}_2\text{O}_2$
  • 3. $\text{Fe}_2\text{O}_3$
  • 4. $\text{Fe}_3\text{O}_4$
Solution:
$\text{Hint: Mass percentage can be defined as the ratio of Mass of the component of the solution and total mass of the solution multiplied by 100\%.}$ $\text{Step 1: Write the given data}$ $\text{Mass percent of iron (Fe)} = 69.9\%$ $\text{Mass percent of oxygen (O)} = 30.1\%$ $\text{STEP 2: Calculate number of moles of iron and oxygen present in oxide.}$ $\text{Number of moles of iron present in the oxide} = \frac{69.90}{55.85} = 1.25$ $\text{A number of moles of oxygen present in the oxide} = \frac{30.1}{16.0} = 1.88$ $\text{STEP 3: Write down the empirical formula using the ratio of iron and oxygen in oxide.}$ $\text{The ratio of iron to oxygen in the oxide,}$ $= 1.25:1.88$ $= \frac{1.25}{1.25} : \frac{1.88}{1.25}$ $= 1 : 1.5$ $= 2 : 3$ $\therefore \text{The empirical formula of the oxide is Fe}_2\text{O}_3.$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}