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Current Question (ID: 7396)

Question:

$\text{In a reaction } \text{A} + \text{B}_2 \rightarrow \text{AB}_2\text{, A will act as a limiting reagent if:}$\n\n$\text{i. 300 atoms of A reacts with 200 molecules of B}_2$\n\n$\text{ii. 2 moles A reacts with 3 moles B}_2$\n\n$\text{iii. 100 atoms of A reacts with 100 molecules of B}_2$\n\n$\text{iv. 5 moles A reacts with 2.5 moles B}_2$\n\n$\text{v. 2.5 moles A reacts with 5 moles B}_2$\n\n$\text{Choose the correct option:}$

Options:

1. $\text{(i), (ii)}$
2. $\text{(i), (ii), (v)}$
3. $\text{(ii), (v)}$
4. $\text{All}$

Solution:

$\text{HINT: Use limiting reagent concept}$\n\n$\text{A limiting reagent determines the extent of a reaction. Let's analyze each case:}$\n\n$\text{Case (i): As per the given reaction, 1 atom of A reacts with 1 molecule of B}_2\text{. Thus, 200 molecules of B}_2 \text{ will react with 200 atoms of A, thereby leaving 100 atoms of A unused. In this case, B}_2 \text{ is the limiting reagent, not A.}$\n\n$\text{Case (ii): As per the reaction, 1 mole of A reacts with 1 mole of B}_2\text{. Thus, 2 moles of A will react with 2 moles of B}_2\text{. Since 3 moles of B}_2 \text{ are available, 1 mole of B}_2 \text{ will remain unused. In this case, A is the limiting reagent.}$\n\n$\text{Case (iii): According to the given reaction, 1 atom of A combines with 1 molecule of B}_2\text{. Thus, all 100 atoms of A will combine with all 100 molecules of B}_2\text{. Hence, the mixture is stoichiometric where no limiting reagent is present.}$\n\n$\text{Case (iv): 1 mole of A combines with 1 mole of B}_2\text{. Thus, 2.5 moles of B}_2 \text{ will combine with only 2.5 moles of A. Since 5 moles of A are available, 2.5 moles of A will be left unreacted. In this case, B}_2 \text{ is the limiting reagent, not A.}$\n\n$\text{Case (v): According to the reaction, 1 mole of A combines with 1 mole of B}_2\text{. Thus, 2.5 moles of A will combine with 2.5 moles of B}_2\text{, and the remaining 2.5 moles of B}_2 \text{ will be left unreacted. In this case, A is the limiting reagent.}$\n\n$\text{Therefore, A acts as the limiting reagent in cases (ii) and (v).}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}