Import Question JSON

Current Question (ID: 7414)

Question:
$\text{The sulphate of the metal M contains } 9.87\% \text{ of M. This sulphate is isomorphous with } \text{ZnSO}_4 \cdot 7\text{H}_2\text{O}. \text{ The atomic weight of M is:}$
Options:
  • 1. $40.3$
  • 2. $36.3$
  • 3. $24.3$
  • 4. $11.3$
Solution:
$\text{Hint: Isomorphous means similar structure}$ $\text{Step 1:}$ $\text{So, the formula of the sulphate of metal would be } \text{MSO}_4 \cdot 7\text{H}_2\text{O}$ $\text{If m is the atomic weight of M}$ $\text{So, molecular weight of } \text{MSO}_4 \cdot 7\text{H}_2\text{O}$ $= m + 32 + 4(16) + 7(18) = m + 222$ $\text{Step 2:}$ $\text{Hence } \% \text{ M} = \frac{m}{m + 222} \times 100 = 9.87$ $\text{or, } 100 m = 9.87 m + 222 \times 9.87$ $\text{or, } 90.13m = 222 \times 9.87$ $\text{or, } m = 24.3$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}