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Current Question (ID: 7439)

Question:
$20 \text{ g of sugar is dissolved in enough water to make a final volume of 2L. The concentration of sugar } (\text{C}_{12}\text{H}_{22}\text{O}_{11}) \text{ in mol L}^{-1} \text{ will be:}$
Options:
  • 1. $0.29 \text{ mol/L}$
  • 2. $0.029 \text{ mol/L}$
  • 3. $0.35 \text{ mol/L}$
  • 4. $0.032 \text{ mol/L}$
Solution:
$\text{Hint: Molarity (M) indicates the number of moles of solute per liter of solution.}$ $\text{Step 1: Write the formula of molarity}$ $\text{Molarity (M) of a solution is given by,}$ $= \frac{\text{Number of moles of solute}}{\text{Volume of solution in liters}}$ $\text{Step 2: Substitute the given values in formula.}$ $\text{Molarity} = \frac{\text{Mass of sugar}}{\text{molar mass of sugar}} \div 2\text{L}$ $= \frac{20\text{g}}{[(12 \times 12) + (1) \times 22 + (11) \times 16]\text{g}} \div 2\text{L}$ $= \frac{20\text{g}}{342\text{g}} \div 2\text{L}$ $= \frac{0.0585}{2\text{L}} \text{ mol } 2\text{L}$ $= 0.029 \text{ mol/L}$ $\therefore \text{Molar concentration of sugar} = 0.029 \text{ mol/L}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}