Import Question JSON

Current Question (ID: 7445)

Question:

$0.50 \text{ mol } \text{Na}_2\text{CO}_3 \text{ and } 0.50 \text{ M } \text{Na}_2\text{CO}_3 \text{ are different because:}$

Options:

1. $\text{Both have different amounts of } \text{Na}_2\text{CO}_3.$
2. $\text{0.50 mol is the number of moles and 0.50 M is the molarity.}$
3. $\text{0.50 mol } \text{Na}_2\text{CO}_3 \text{ will generate more ions.}$
4. $\text{None of the above.}$

Solution:

$\text{Hint: Unit mol represents the number of moles and M represents molarity}$ $\text{Explanation:}$ $0.50 \text{ mol } \text{Na}_2\text{CO}_3 \text{ refers to a number of moles but } 0.50 \text{ M refers to the molarity of the solution.}$ $\text{Molarity or molar concentration is the number of moles of solute per liter of solution. For molarity, volume is 1 litre.}$ $\text{So, option 2 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}