Import Question JSON

Current Question (ID: 7448)

Question:

$\text{If the diameter of a carbon atom is 0.15 nm, the number of carbon atoms that can be placed side by side in a straight line across the length of the scale of length 20 cm long will be:}$

Options:

1. $1.33 \times 10^7$
2. $5.46 \times 10^8$
3. $1.33 \times 10^9$
4. $2.36 \times 10^8$

Solution:

$\text{Hint: Conceptual question. Use basic concepts to solve this question.}$ $\text{Length of scale} = 20 \text{ cm} = 20 \times 10^{-2} \text{ m}$ $\text{Diameter of a carbon atom} = 0.15 \text{ nm} = 0.15 \times 10^{-9} \text{ m}$ $\text{One carbon atom occupies} = 0.15 \times 10^{-9} \text{ m}$ $\text{Number of carbon atoms that can be placed in a straight line} = \frac{20 \times 10^{-2}}{0.15 \times 10^{-9}} = 1.33 \times 10^9$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}