Import Question JSON

Current Question (ID: 7449)

Question:

$\text{The diameter of a zinc atom is 2.6 Å. If zinc atoms are arranged side by side lengthwise, number of atoms present in a length of 1.6 cm would be:}$

Options:

1. $5.153 \times 10^7$
2. $6.153 \times 10^7$
3. $4.153 \times 10^9$
4. $6.153 \times 10^3$

Solution:

$\text{Hint: Number of zinc atoms} = \frac{\text{Length of the arrangement}}{\text{Diameter of zinc atom}}$ $\text{Length of the arrangement} = 1.6 \text{ cm} = 1.6 \times 10^{-2} \text{ m}$ $\text{Diameter of zinc atom} = 2.6 \times 10^{-10} \text{ m}$ $\therefore \text{Number of zinc atoms present in the arrangement}$ $= \frac{1.6 \times 10^{-2} \text{ m}}{2.6 \times 10^{-10} \text{ m}} = 0.6153 \times 10^8 = 6.153 \times 10^7$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}