Import Question JSON

Current Question (ID: 7455)

Question:
$\text{The number of electrons in the species } \text{H}_2^+, \text{H}_2, \text{O}_2^+, \text{ are respectively:}$
Options:
  • 1. $15, 2, 1$
  • 2. $15, 1, 2$
  • 3. $1, 2, 15$
  • 4. $2, 1, 15$
Solution:
$\text{HINT: Number of electrons = Number of protons = atomic number (Z) for a neutral atom.}$ $\text{Explanation:}$ $\text{H}_2^+\text{:}$ $\text{Number of electrons present in hydrogen molecule } (\text{H}_2) = 1 + 1 = 2$ $\text{Number of electrons in } \text{H}_2^+ = 2 - 1 = 1$ $\text{H}_2\text{:}$ $\text{Number of electrons in } \text{H}_2 = 1 + 1 = 2$ $\text{O}_2^+\text{:}$ $\text{Number of electrons present in oxygen molecule } (\text{O}_2) = 8 + 8 = 16$ $\text{Number of electrons in } \text{O}_2^+ = 16 - 1 = 15$ $\text{So, option 3 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}