Import Question JSON

Current Question (ID: 7461)

Question:

$\text{The number of protons, neutrons and electrons in } {}^{175}_{71}\text{Lu} \text{ respectively, are:}$

Options:

1. $104, 71 \text{ and } 71$
2. $71, 71 \text{ and } 104$
3. $175, 104 \text{ and } 71$
4. $71, 104 \text{ and } 71$

Solution:

$\text{Hint: Mass number = number of proton + number of neutron.}$ $\text{Explanation:}$ $\text{We know that, mass number = number of proton + number of neutron.}$ $\text{For } {}^{175}_{71}\text{Lu}:$ $\text{Mass number (A) = 175}$ $\text{Atomic number (Z) = 71}$ $\text{Number of electrons = 71 (since the atom is neutral)}$ $\text{Number of protons is equal to atomic number = 71}$ $\text{Number of neutrons = atomic mass - number of protons}$ $= 175 - 71 = 104$ $\text{Therefore: Protons = 71, Neutrons = 104, Electrons = 71}$ $\text{So, option 4 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}