Import Question JSON

Current Question (ID: 7463)

Question:

$\text{The number of electrons in } {}_{19}\text{K} \text{ with quantum numbers n=3; l=0 is/are:}$

Options:

1. $2$
2. $1$
3. $4$
4. $3$

Solution:

$\text{Hint: Find which orbital is represented by n=3 and l=0}$ $\text{The electronic configuration of } {}_{19}\text{K} \text{ is:}$ $1s^2 2s^2 2p^6 3s^2 3p^6 4s^1$ $\text{Quantum numbers n=3 and l=0:}$ $\text{n=3 indicates the third energy level}$ $\text{l=0 indicates an s orbital}$ $\text{Therefore, n=3 and l=0 represent the 3s orbital}$ $\text{From the electronic configuration, the 3s orbital contains } 3s^2$ $\text{This means the 3s orbital has 2 electrons}$ $\text{Therefore, the number of electrons in } {}_{19}\text{K} \text{ with quantum numbers n=3, l=0 is 2.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}