Import Question JSON

Current Question (ID: 7471)

Question:

$\text{The total number of electrons present in one mole of methane is:}$

Options:

1. $6.023 \times 10^{23}$
2. $6.023 \times 10^{24}$
3. $6.023 \times 10^{22}$
4. $1.619 \times 10^{23}$

Solution:

$\text{Hint: Use mole concept}$ $\text{STEP 1: Write down the number of electrons present in one molecule of methane.}$ $\text{Number of electrons present in 1 molecule of methane CH}_4 = [1(6) + 4(1)] = 10$ $\text{STEP 2: Find out the number of electrons in one mole of methane.}$ $\text{Number of electrons present in 1 mole i.e., } 6.023 \times 10^{23} \text{ molecules of methane}$ $= 6.023 \times 10^{23} \times 10 = 6.023 \times 10^{24}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}